parallel wrote:The table says a 2" pipe carries ~10 lb/min of steam (1 psi pressure drop).
For one hour that is 600lb of steam
Say 1150 btu/lb to boil water.
1150 x 600 = 690,000 BTU
1 kW = 3412 BTU
So 690,000 BTU = 202 kW
You were right. - I don't normally use kW for heat...
Something is screwy. Even 50 psi drop only doubles the capacity.
I'll have to think about it.
From the same table one would need a 4 - 5" pipe
From the chart you reference, if the pressure is 50psi then the pipe can transmit 20lbs per minute with a loss of 1psi over a distance of 480 inches.
From equation 44 in your link, the pressure drop varies as the square of the steam flow. If you quintuple the flow the pressure drop would be 25 psi, over 480inches.
All this is academic however, because, from the readily available video at ny teknik, we can see that the steam manifold internal to the shipping container much greater than 2" in diameter. In fact, if we assume that it is 4" in diameter, then combining the data from table 66 and 68 from your link we can see that the device is completely consistent with 1 MW of steam flow and the short 2" outlet pipe (assume a 2.5psi pressure loss over a 48" length from equation 44), serves as a method of generating back pressure in the instrument, raising the internal pressure of the generator to ~25psi absolute pressure. Again from table 68 we can see that this corresponds to a steam flow of just over 60lbs per minute through a 2" outlet.
In short your link shows that, at 1MW, the possibility of the device exploding is remote. If the, in the end, the output is only 167kW, then the possibility of an explosion is even more unlikely.