I'm guessing that the low power run @ 5kv was the one that didn't generate much light.
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Test result details - they detected light as well?
He used D-D, so two fusions per neutron, and about 0.001 watts. With D-T he would probably get 10 to 30 times as much fusion, but tritium is too much trouble for an experiment.TallDave wrote:I get 1E+9 fusions x 17.6 MeV per fusion x 1.6E-19 eV per joule = .00282 joules/second = .00282 watts. Seems pretty dim.
Fusion is easy, but break even is horrendous.
TallDave's original calculation is correct. If you read the transcript of Bussard's video, it's clear he was extrapolating those three neutrons back to a per second number, so
P = 1e9 fusions/s * 17.6 MeV/fusion * 1.6e-19 J/eV = 2.82 mW
Q << 1.
Edit: Fixed the Joules/eV units. It all comes out in the wash if you remember the units.
P = 1e9 fusions/s * 17.6 MeV/fusion * 1.6e-19 J/eV = 2.82 mW
Q << 1.
Edit: Fixed the Joules/eV units. It all comes out in the wash if you remember the units.
Ah yes, good point.pstudier wrote:He used D-D, so two fusions per neutron, and about 0.001 watts.
PMTs are probably sensitive to detect that, but reading through the notes again it seems more likely their point is just that the light pulse was indicative of the conditions that were likely for fusion, making it additional evidence that the neutron counts were not just noise as they happened simultaneously with the light pulses.