
Note the 'possibly' in the title. Using wildly optimistic, but at least possible, peramiters to figure the performance of an imaginary Polywell, and ignoring pesky problems like Bremsstrulung, plasma boundary arguments, thermalization, potential well shape, vacuum concerns, conversion efficiencies, material limits, etc, etc... a couple of example BFRs' (remember the threads proposing a name for a working Polywell fusion system?).
Estimates start from a base of 1 milliwatt output for WB6 , fusion crossection gains at higher voltages, and B4 r3 scaling.
Minimal Near break even size reactor:
Fuel D-D
Diameter = ~ 62 cm = ~ 10X size scaling
B -field = ~ 3.3 Tesla = ~ 1,000,000x scaling
Optimization of geometry = ~ 5X scaling
Potential well ~ 100,000 V = ~ 30X scaling
Multiply all of these together and the machine would have a fusion output of ~ 1,500,000 watts. Already near break even.
If the B- field was increased to ~ 6 Tesla, the output would be ~ 18 MW
WB 8 performance might be:
Fuel D-D
Diameter 43 cm (just for the heck of it) =~ 3X scaling
B-field = ~0.8 Tesla = ~ 4,000X scaling
Optimization of geometry (same truncated cube, but modification of nubs, spacing) = ~ 1.2 X scaling
Potential well ~ 30,000 volts = ~15X scaling
A maximal output for this imagined WB8 with these assumptions may be up to ~ 210 watts.
These are obviously extreme results, but they suggest that a 3 meter magrid diameter for a commercial reactor may be a very conservative goal, provided my assumptions are not too far off, and losses scale as hoped.
Such a reactor might have:
D-D fuel
Diameter = 300 cm = ~ 1000X scaling
B- field = ~ 3.3 Tesla = ~ 1,000,000X scaling
Optimization of geometry = ~ 5X scaling
Potential well = ~100,000 volts = ~30X scaling
Fusion output would be ~ 150 MW, even with this 'modest' magnetic strength. Even if there is no 'Optimization of geometry' gains past WB6 levels, only a mild increase in magnetic strength would compensate.
Losses for WB 6 was ~ 500,000 watts ( ~40 amp ( during the brief time when the machine was operating near Beta= 1 conditions) x 12,000 volts electron input, plus ~ 1000 amps x 12 volt magnet drive). I have seen Dr. Nebel mention 8 MW, but I don't know where this number came from, unless he was thinking of the power input for an anticipated break even system. I'm uncertain how the electron input energy would scale. If 80 amps at 100,000 volts is needed, that would be 8 MW. Increased power input to the stronger magnets would be relatively small even with copper wires (superconductors biggest advantage here may be avoidance of Ohmic heating and volume concerns, rather than need to maximize Q). How much more electron current would be needed to maintain a net excess of electrons over the increasingly heavy ion loading (and escaping charged fusion ion product unloading) is a mystery for me. I used a factor of two, merely because it matched my interpretation of Dr. Nebel's number (it is always convenient to cook the numbers

Dan Tibbets