for 3MeV is about 1.2595 Tesla,MSimon wrote:What is the strength required of the magnets in order to prevent 3 to 5 MeV alphas from hitting the walls?
I would choose 3 Tesla or higher.
My calculations are correct. I was starting from this point:MSimon wrote:I think your calculations are incorrect.
Please show all your steps.
In addition you assume all reactions take place in a small core.
And how do you prevent divergence? And how do you keep your fuels in the core? How do you get your exhaust gases to go around the bends without hitting the walls ?
How do you handle cusp losses?
Where did the "10" come from?cosmos wrote:My calculations are correct. I was starting from this point:MSimon wrote:I think your calculations are incorrect.
Please show all your steps.
In addition you assume all reactions take place in a small core.
And how do you prevent divergence? And how do you keep your fuels in the core? How do you get your exhaust gases to go around the bends without hitting the walls ?
How do you handle cusp losses?
10 × (3MeV) / (207.60172×E-27 Kg) = 1.44507E32 eV/Kg
Sorry, I am very busy for doing calculations for you.
small core? divergence?
Penning Traps has no problem of this type and it confines efficiently the fuel.
Please read more about Penning Traps.
cusp losses? I use continuous injection of ions and there is no recirculation of electrons.
Heck of a rocket ship you have there Johnny.The travel between Earth and Alpha Centauri star, including acceleration and deceleration, will take 2 years and 11 months and a decaborane consumption of 275.2Kg, reaching a maximum velocity of 3.27131×10E9Km/h, about three times the speed of light, at the midway.
I cannot resist the question - who, exactly, fully proved Newtonian physics?The Newtonian physics has no restrictions about the velocity. Only the Theory of Relativity restricts the velocity to speed of light...
The Theory of Relativity was not fully proven...
I only share same opinions and critiques with other people concerning some theories. It is only critiques and opinions.chrismb wrote:Cosmos;
I cannot resist the question - who, exactly, fully proved Newtonian physics?The Newtonian physics has no restrictions about the velocity. Only the Theory of Relativity restricts the velocity to speed of light...
The Theory of Relativity was not fully proven...
If the inference that the theory of relativity is unproven, then why are you implicity accepting that the 8.68MeV/c^2 rest-mass loss in the p+11B->3He reaction results in 8.68MeV of energy? Please do let me know if you need more explanation of this question.
best regards,
Chris MB.
Maybe the polemic is from this:In physics, the electron volt (eV) is a unit of energy. By definition, it is equal to the amount of energy gained by a single unbound electron when it accelerates through an electrostatic potential difference of one volt.
the Tsiolkovsky rocket equation diverges a lot from E=½mv²The formula E=½mv² refers to the action and reaction (Newton's third law) between the spacecraft and the exhausting products and not between the spacecraft and the origin point or launching site.
In the outer space, half of the energy goes to the exhausting products:
½E=½mv² → E=mv² → 200e6=500000× v²→ v=20 m/s → a=∆v/∆t → a=20m/s² → g-force= 2.0 g
Science is not based on opinions, it is based on repeatable observations that support some predicate logic.cosmos wrote: I only share same opinions and critiques with other people concerning some theories. It is only critiques and opinions.
No worries mate. You can't reach the speed of light if you have any rest mass. I suggest starting with a kilo or two. That should be enough to prevent the problem from arising.cosmos wrote:You are right.
E/m=66.03921e12 J/Kg
v=SQRT(2E/m) = 11.49254e6 m/s
v=SQRT(c^2-[c^3/({E/m}+c^2)]^2) = 11.48622e6 m/s
I am not an expert in Relativity.
I rely on acceleration (g-force) for generating a gravitational effect in the spacecraft.
When the matter is acceleration, the Relativity sounds very strange for me.
At speed of light, will the g-force disappear?