The Kiteman Konjecture
Posted: Fri Jun 10, 2011 10:19 pm
The Kiteman Konjecture
I started this search with the idea of finding a plausible physics based process to explain the claimed excess heat of the Rossi Reactor while also meeting some of the other apparent characteristics and known statements. I in no way claim that this is the Rossi process, just that … well, it may be. In truth, I would probably fall over faint if it turned out to be correct, but it wouldn’t upset my world view one iota.
[SPECULATION]
Start with an assumed nano-particulate Ni powder enriched in the higher isotopes, 62 and 64. One method for simple enrichment is postulated below.
Bathe in H2 gas. Heat as needed until hydrides form. I have not done any study to try to predict exactly what density of H in the Ni lattice is required, but I have chosen to do my limited numbers base on 1:1. Since these are supposed to be nano-particles, quick loading may be a matter of course.
Given a density of free electrons in the material (2 electrons per nickel, one from the last P orbital and one from the H), a plasmon with a frequency of about 3 Peta-Hertz, in the near to mid UV, can form. A plasmon is a “quantum of oscillation”. I take this to mean that a matrix of electrons start oscillating together at the same frequency. The heating of the lattice may be related to tuning the plasmon to a specific frequency as plasmon frequency is known to be temperature sensitive.
Apply UV laser light. (DPSS, quantum dot? I notice that the Rossi device has a rather long, water cooled segment BEFORE the apparent reactor chamber. This space may be used to hold and cool a UV laser.) When the frequencies of the UV laser and the plasmon coincide, they will interact to form a polariton. A polariton is a “quasi-particle”. I take this to mean that plasmon gets polarized and locked into a single matrix of electrons. I also take this to mean that the electrons are all oscillating in sync with the UV laser.
* Polaritons have an interesting characteristic. Unlike electrons and the quarks that make up nucleons, which are fermions, polaritons are bosons. Fermions are subject to Fermi-Dirac statistics which, among other things, is why there are specific, exclusive, orbital shells for electrons and it seems for nucleons too. To quote wikipedia, “by definition, fermions are particles which obey Fermi–Dirac statistics: when one swaps two fermions, the wavefunction of the system changes sign.[1] This "antisymmetric wavefunction" behavior implies that fermions are subject to the Pauli exclusion principle, i.e. no two fermions can occupy the same quantum state at the same time. This results in "rigidity" or "stiffness" of states that include fermions (atomic nuclei, atoms, molecules, etc.), so fermions are sometimes said to be the constituents of matter, while bosons are said to be the particles that transmit interactions (i.e. force carriers) or the constituents of electromagnetic radiation.”
* Electrons, being fermions, can’t normally wander around inside the filled electron shells of atoms. What this suggests is that since bosons are NOT subject to Pauli’s exclusion principle, the polariton, the lock-step matrix of electrons, CAN pass thru the electron shells. Indeed, since the charges are still active, the now polarized and cross linked plasmon might align itself with the nickel lattice such that the electrons are oscillating in line between pairs of nuclei.
* Supposing the active area of the reaction is highly loaded with H, and including the single electron of the outer shell of the nickel, this results in two electrons per NiH which, if aligned as assumed above, would set up the structure X{H-e-Ni-e}.
* Electrons starting at ~350k (~1.26E+05 m/sec) and oscillating at ~ 3PHz will displace about 5 pm which is of a near order to the radius of a nickel atom (124 pm) but perhaps not enough to have a desired effect.
Adjust the intensity of the UV input to heat the plasmon till the electron is reaching closer to the two nuclei. IF the electron in the polariton gets close enough to each nucleus it should exert a force on the H sufficient to attract it toward the Ni. The H should accelerate until it reaches the center of the oscillation of the electron. Inertia will take it further toward the Ni nucleus, and along with the slight residual shielding of the proton by the oscillating electron, might very well make it close enough to the Ni to be captured. Since the polariton electrons are conceptually getting VERY close to the newly excited nucleus, they could provide the particle for the shedding of the excitation energy. Indeed, if the {H-e-Ni-e} structure does exist, the polariton would provide not one but TWO electrons to carry away the excitation energy. If so, the remaining energy to be shed by gamma radiation may possibly be at or near the energy of the UV laser and dump itself into that beam. This may be the source of the energy spike phenomenon that has been reported. Alternatively, it may be in the soft to mid X-ray range and be the reason for the “2 cm of lead” shielding.
Naturally, being enclosed in a metal shell, the very high energy (even hyper-relativistic) electrons (not technically beta particles since they did not originate from a nucleon) would dump their energy into the surroundings as heat.
This MAY be how the Rossi machine works, if indeed it does.
Several things come to mind.
Ni isotopes have a “magic number” of protons which would mean they are all tightly bound into their shells. As a result, they shouldn’t be readily available to react to the presence of the conceptual polariton electrons. The neutrons on the other hand exceed the magic number and to a degree should be free to wander the surface. As the electrons approach the nucleus its charge might attract the wandering neutron via the nuclear equivalent of Van der Waal’s forces, aligning then with the electron/proton pair. Indeed, there may become a pile-up of local neutrons in line with the electrons. These neutrons, or piles of neutrons, may provide just the slight extra boost needed to make the reaction happen. It might also explain what Rossi meant by his “extra hooks” remark.
Since 61Ni is the middle of the pack of stable Ni isotopes, there may be something that buries the first 5 neutrons beyond the “magic number” in the nucleus for stability reasons. If so, this would leave 62Ni with one extra “hook” and 64Ni with three.
If this is indeed the case, it could help explain why the Cu ratio is near natural. The natural ratio of 62Ni to 64Ni is about 4:1. The enrichment process described below should cause a slight over enrichment of the heavier isotope. If the probability of reaction is also related to excess neutron count, the combination may very well result in closer to 70:30.
As for the lower mass Nickel isotopes, if they absorb a neutron, the Copper isotopes they would create would decay back to Ni by beta+ decay with half lives below 3.5 hours in every case.
Cu isotopes have one proton MORE than the magic number. If this proton is free to oscillate opposite to the polariton, it may provide sufficient additional coulomb forces to prevent or greatly minimize any additional proton absorption. This could explain why there is little if any Zinc detected.
Part of the whole issue is whether enrichment is plausible. I believe it may be not only plausible but fairly simple if you have expertise with micro and nano particles. The following is one possible scenario.
Buy Ni powder that is too big but of consistent particle size. If such in not available, then sift for size.
Introduce oversize particles into reformation chamber that:
1. melts the particles;
2. spins them to just below failure;
3. waits a bit while the heavier isotopes drift outwards;
4. disrupts the molten drop such that the outer, enriched parts fly outward and the remainder, depleted part drops down; and
5. captures the enriched drop in a manner to create the particle structure conditions you want while solidifying it.
If you want the surface to be crazed with micro-cracks, then a quick quench might achieve this. If a single crystal is more desired, a slow cooling may be needed.
The disruption might be accomplished in any of a number of ways, but my favorite is to touch the outer bulge of the oblate molten spheroid with small diameter laser dots. This process may require flickering to get the specific points to heat up. Since surface tension gets lower with heat, the heated spots should begin to extrude a stream of molten metal that would quickly nucleate into nano-drops. The remaining surface would pull the remainder of the original drop into a smaller drop and it would continue to fall down.
[/SPECULATION]
Please be nice!
I started this search with the idea of finding a plausible physics based process to explain the claimed excess heat of the Rossi Reactor while also meeting some of the other apparent characteristics and known statements. I in no way claim that this is the Rossi process, just that … well, it may be. In truth, I would probably fall over faint if it turned out to be correct, but it wouldn’t upset my world view one iota.
[SPECULATION]
Start with an assumed nano-particulate Ni powder enriched in the higher isotopes, 62 and 64. One method for simple enrichment is postulated below.
Bathe in H2 gas. Heat as needed until hydrides form. I have not done any study to try to predict exactly what density of H in the Ni lattice is required, but I have chosen to do my limited numbers base on 1:1. Since these are supposed to be nano-particles, quick loading may be a matter of course.
Given a density of free electrons in the material (2 electrons per nickel, one from the last P orbital and one from the H), a plasmon with a frequency of about 3 Peta-Hertz, in the near to mid UV, can form. A plasmon is a “quantum of oscillation”. I take this to mean that a matrix of electrons start oscillating together at the same frequency. The heating of the lattice may be related to tuning the plasmon to a specific frequency as plasmon frequency is known to be temperature sensitive.
Apply UV laser light. (DPSS, quantum dot? I notice that the Rossi device has a rather long, water cooled segment BEFORE the apparent reactor chamber. This space may be used to hold and cool a UV laser.) When the frequencies of the UV laser and the plasmon coincide, they will interact to form a polariton. A polariton is a “quasi-particle”. I take this to mean that plasmon gets polarized and locked into a single matrix of electrons. I also take this to mean that the electrons are all oscillating in sync with the UV laser.
* Polaritons have an interesting characteristic. Unlike electrons and the quarks that make up nucleons, which are fermions, polaritons are bosons. Fermions are subject to Fermi-Dirac statistics which, among other things, is why there are specific, exclusive, orbital shells for electrons and it seems for nucleons too. To quote wikipedia, “by definition, fermions are particles which obey Fermi–Dirac statistics: when one swaps two fermions, the wavefunction of the system changes sign.[1] This "antisymmetric wavefunction" behavior implies that fermions are subject to the Pauli exclusion principle, i.e. no two fermions can occupy the same quantum state at the same time. This results in "rigidity" or "stiffness" of states that include fermions (atomic nuclei, atoms, molecules, etc.), so fermions are sometimes said to be the constituents of matter, while bosons are said to be the particles that transmit interactions (i.e. force carriers) or the constituents of electromagnetic radiation.”
* Electrons, being fermions, can’t normally wander around inside the filled electron shells of atoms. What this suggests is that since bosons are NOT subject to Pauli’s exclusion principle, the polariton, the lock-step matrix of electrons, CAN pass thru the electron shells. Indeed, since the charges are still active, the now polarized and cross linked plasmon might align itself with the nickel lattice such that the electrons are oscillating in line between pairs of nuclei.
* Supposing the active area of the reaction is highly loaded with H, and including the single electron of the outer shell of the nickel, this results in two electrons per NiH which, if aligned as assumed above, would set up the structure X{H-e-Ni-e}.
* Electrons starting at ~350k (~1.26E+05 m/sec) and oscillating at ~ 3PHz will displace about 5 pm which is of a near order to the radius of a nickel atom (124 pm) but perhaps not enough to have a desired effect.
Adjust the intensity of the UV input to heat the plasmon till the electron is reaching closer to the two nuclei. IF the electron in the polariton gets close enough to each nucleus it should exert a force on the H sufficient to attract it toward the Ni. The H should accelerate until it reaches the center of the oscillation of the electron. Inertia will take it further toward the Ni nucleus, and along with the slight residual shielding of the proton by the oscillating electron, might very well make it close enough to the Ni to be captured. Since the polariton electrons are conceptually getting VERY close to the newly excited nucleus, they could provide the particle for the shedding of the excitation energy. Indeed, if the {H-e-Ni-e} structure does exist, the polariton would provide not one but TWO electrons to carry away the excitation energy. If so, the remaining energy to be shed by gamma radiation may possibly be at or near the energy of the UV laser and dump itself into that beam. This may be the source of the energy spike phenomenon that has been reported. Alternatively, it may be in the soft to mid X-ray range and be the reason for the “2 cm of lead” shielding.
Naturally, being enclosed in a metal shell, the very high energy (even hyper-relativistic) electrons (not technically beta particles since they did not originate from a nucleon) would dump their energy into the surroundings as heat.
This MAY be how the Rossi machine works, if indeed it does.
Several things come to mind.
Ni isotopes have a “magic number” of protons which would mean they are all tightly bound into their shells. As a result, they shouldn’t be readily available to react to the presence of the conceptual polariton electrons. The neutrons on the other hand exceed the magic number and to a degree should be free to wander the surface. As the electrons approach the nucleus its charge might attract the wandering neutron via the nuclear equivalent of Van der Waal’s forces, aligning then with the electron/proton pair. Indeed, there may become a pile-up of local neutrons in line with the electrons. These neutrons, or piles of neutrons, may provide just the slight extra boost needed to make the reaction happen. It might also explain what Rossi meant by his “extra hooks” remark.
Since 61Ni is the middle of the pack of stable Ni isotopes, there may be something that buries the first 5 neutrons beyond the “magic number” in the nucleus for stability reasons. If so, this would leave 62Ni with one extra “hook” and 64Ni with three.
If this is indeed the case, it could help explain why the Cu ratio is near natural. The natural ratio of 62Ni to 64Ni is about 4:1. The enrichment process described below should cause a slight over enrichment of the heavier isotope. If the probability of reaction is also related to excess neutron count, the combination may very well result in closer to 70:30.
As for the lower mass Nickel isotopes, if they absorb a neutron, the Copper isotopes they would create would decay back to Ni by beta+ decay with half lives below 3.5 hours in every case.
Cu isotopes have one proton MORE than the magic number. If this proton is free to oscillate opposite to the polariton, it may provide sufficient additional coulomb forces to prevent or greatly minimize any additional proton absorption. This could explain why there is little if any Zinc detected.
Part of the whole issue is whether enrichment is plausible. I believe it may be not only plausible but fairly simple if you have expertise with micro and nano particles. The following is one possible scenario.
Buy Ni powder that is too big but of consistent particle size. If such in not available, then sift for size.
Introduce oversize particles into reformation chamber that:
1. melts the particles;
2. spins them to just below failure;
3. waits a bit while the heavier isotopes drift outwards;
4. disrupts the molten drop such that the outer, enriched parts fly outward and the remainder, depleted part drops down; and
5. captures the enriched drop in a manner to create the particle structure conditions you want while solidifying it.
If you want the surface to be crazed with micro-cracks, then a quick quench might achieve this. If a single crystal is more desired, a slow cooling may be needed.
The disruption might be accomplished in any of a number of ways, but my favorite is to touch the outer bulge of the oblate molten spheroid with small diameter laser dots. This process may require flickering to get the specific points to heat up. Since surface tension gets lower with heat, the heated spots should begin to extrude a stream of molten metal that would quickly nucleate into nano-drops. The remaining surface would pull the remainder of the original drop into a smaller drop and it would continue to fall down.
[/SPECULATION]
Please be nice!