Colonel_Korg wrote:I'n new to this forum and my physics is quite rusty, so please forgive me if theses questions have already been asked (I looked and didn't see any quite like them),
Welcome! I'm not a physics great either, but I've hung around here a bunch and I hope I can answer your questions, at least to the best of my ability.
Question 1: During his google talk, Dr Bussard mentioned that the coils to form the polywell should be an even number at the cusps so that the magnetic fields on any two ajacent coils could be opposit? Am I wrong on this?
Others may correct me, but I'd say yes-and-no.
My understanding of that even-numbered criterion was that that applied to the polyhedron the polywell was based on. The idea is to have each face of the polyhedron be a solonoid, and each edge of the polyhedron be a conductor. The magnetic field should also be as symmetric as possible.
In order for this to work, the direction of current on each edge must be such that each face forms a loop. A moments reflection shows that this also means that the direction (clockwise/counterclockwise) of the current loop on each face must be opposite for faces which share an edge. The polarity of adjacent faces is reversed.
The latter is what causes the "even number" criterion Dr. Bussard was talking about. Requiring no two adjacent faces to have the same polarity is the same as saying that the underlying polyhedron can be two-colored: each face is red or blue, and no two adjacent faces have the same color. If you look at any vertex of the polyhedron, it's easy to see that all the vertices must have an even number of edges going into it. If you had an odd number, then you must have two adjacent faces of the same polarity.
You can see this with the platonic solids: It's impossible to two-color the faces of a tetrahedron, cube, dodecahedron, or icosahedron because the order of their vertices are 3, 3, 3, and 5 respectively. It's possible to two-color an octohedron, and it's vertices are of order 4.
This does suggest the question: If it's impossible to two-color a cube, if a cube fails Dr. Bussard's even-number of coils around a cusp issue, then why are the polywell designs people are talking about cubes? Or dodecahedrons, which also fail that criterion.
The answer is that it isn't really a "cube", for the purpose of Bussard's analysis. The 6 physical coils also make 8 "virtual coils", with opposite polarity, centered around the vertices of the cube. The only place you have two coils of the same polarity approaching each other is along the edges of the cube, where two virtual coils and two physical coils "meet". So the underlying polyhedral structure of the WB-6 (And WB-7) isn't cubical, but rather cuboctahedral. A cuboctahedron has 6 square faces, 8 triangular faces, and 12 vertices, each of which is of order 4, which meets Dr. Bussard's evenness criterion.
As far as cusps go, the cuboctahedron has 24 cusps, one for each face, and one for each vertex. In the polywell, the cusps corresponding to the vertices are the dreaded "line cusps", where high electron losses are traditionally suspected of coming from, while the cusps corresponding to faces are "point cusps". So one way of describing what Bussard was talking about is that an even number of coils, physical and virtual, must meet at each line cusp.
If I'm right, I have not seen this configuration of 8 coils in an octahedron arrangement mentioned on this site.
The nice thing about the octahedron is it limits the cusps to 6 cusps and 8 "faces".
If you look at it with the same sort of analysis I applied to the cube, you'll find that it has 8 physical coils, 6 virtual coils, and 12 places where coils come together, in exactly the same configuration as a cuboctahedron. The difference between it and that of the "standard" cubical polywell is the swapping of physical and virtual coils.
Question 2: In the pB11 reaction, the 3 He4 nuclei leave the central containment area at a fairly high (3+Mev and 2+Mev) Is the magnetic fields on the coils enough to deflect them just enough so they don't hit the coils on their way to the outer power generation grid? The He4 particles hitting the coils could cause them to heat up or worse cause spurttering to the metal?
Nope. the magnetic fields aren't going to be anywhere nearly strong enough to do squat to the alphas. A lot of discussion has occured here on how to (a) cool the coils to get rid of the heat caused by impinging alphas, or (b) minimize the cross-section of the coils as seen from the fusion region, so as to minimize the heating caused by impinging alphas, or (c) both.
Thanks for everyone patience with the new comer.
No problem. Again, welcome.
Paul Smith
Tampa, FL[/quote]