Perhaps I'm confused, but I don't follow your reasoning. Particles can interact with particles, but I believe the charged particle interactions are dominated by space charge considerations. Fusion plasmas are generally weakly coupled. This means that the behavior of the plasma is not dominated by the oppositely charged particles pairing up. There is some of this effect (it is what helps to form a parabolic potential well) but for containment issues it is a minor influence.erblo wrote:I didn't consider any particle-particle interactions, just the grid. The question was if he was using SI units, i.e. C and C/m. If thats the case I interpret the first "wb32" video (xyz-view) as him having a ~10C/m charge on the grid. Since the length of the 15cm "wb32" grid is about 7.4m that is a total of ~74C on the grid and a potential of ~ 4.4*10^12V in the center (compared to 0V at infinite radius). I then compared this to the potential at 3m giving a difference of about 4.3TV (should perhaps have been 3 radii = 0.45m and 3.8TV).D Tibbets wrote:
Your math/ assumptions are not right. Perhaps you are assuming a population of ~ 10^22 electrons/ M^3 in the Wiffleball and the associated coulomb repulsion (which would be huge)...
I neglected the particles because the net charge was set to 10^-8C << 74C![]()
(By the way, is this total or per particle? Doesn't really matter in this case.)
The space charge (the force pulling in or pushing out against individual charged particles) is determined by the net excess of one charge over the other. Again this is ~ determined by the excess electrons in a ration of ~ 1.000001. This makes the plasma non neutral. I used the density of ~ 10^22 charged particles / M^3 as this is a claimed capacity of a large Polywell. In this case there would be 10^16 excess electrons /M^3, and it is only this number of negative charged particles that creats the negative space charge. The other electrons and ions cancel each other out. In this example there is ~ 0.001 Coulombs of net negative charge/ M^3 within the Wiffleball, and this is what helps to create the potential well. The pressure against the magnetic field is a cumulative effect of all of the charged particles. But this is due to their kinetic energy, not their individual charges (the individual charges are nessisary for them to interact with the magnetic field, but does not contribute much to the pressure directly. There is discussion of the pressure effects against the magnetic field (that inflates it) in the 2008 patent application.
So, my understanding is that the Polywell will have perhaps 10^-3 Coulombs of unbalanced charge that tries to push the electrons out and pull the ions in. Of course inside the magrid , the charged particles ignore any potential on the coils. The pressure on the magrid generated field is something like P= n* V^2. The velocity is squared, so it has a dominate effect on the pressure. A balanced neutral plasma would interact with the magnetic field much like a gas in a balloon. the inflation is dependent on the density and temperature. The charge is irrelevant (except of course you have to have individually charged particles to interact with the magnetic field like a gas does with the surface of a balloon).
I don't know what parameters the sims are using, but the above illustrates the the charges in a Polywell.
Also, I don't know what you intend when you state a potential needed to contain the electrons. That is nonsensical to me. The electrons are not contained electrostatically, but magnetically. There are two (or three considerations if you consider recirculation). The magnetic field strength has to be strong enough to turn the high speed electrons at the bottom of their potential well before they reach the magnet can surface, and the cusps need to be small enough that the electrons hit these sites rarely. The electrons that hit the cusps and pass outside are lost from containment. But recirculation cheats and reclaims most of these escaped electrons. Because of inneficiencies in electron injection. The potential on the magrid can reclaim (and reset the energy) of these escaped electrons unless they have been upscattered by more than ~ 20%.
Thermalization issues are important. The originally monoenergetic electrons collide repeatedly within the Wiffleball and tend towards thermalization, but the lifetime of the electrons before they hit a cusp is short enough that full thermalization does not occur before escape. I don't know if there are any other thermalization impeding effects for the electrons as there are for ions (annealing). So the high energy tail does not fully develop, and a presumably large portion of this developing high energy tail electrons are still below the 20% limit so they are reclaimed and reset by recirculation.. Those above the ~ 20% limit fly to the wall and are removed from the system so they cannot continue to contribute to thermalization. Of course all of this implies energy loss, but in balance it is tolerable and beneficial to the operation of the machine.
Talking of the ions, which are electrostatically contained, A. Carlson claimed that several million volt potential wells would be required to contain most of the upscattered ions, but this was based on thermalized plasmas and ignored the claimed annealing. In one paper Bussard gave a number ~ twice the desired potential well to contain most of the upscattered ions. I assume this reflects the efficiency of the claimed annealing. Of course, I don't know how you could have an accelerating potential well that was different from the containment potential well. In that case, Bussard recognized that the mildly upscattered ion could climb above the potential well (extend past the Wiffleball border), but it would not escape unless it hit a cusp. It would be turned by the magnetic field. This tends to decrease convergence, but hangs on to the ion. This is not as bad as pure magnetic ion confinement schemes, because only a minority of the ions reach this condition, so ion ExB drift and ion cusp losses are restrained, apparently to such an extent that most of the ions (or at least enough of them) are expected to fuse before they manage to escape.
Dan Tibbets