MSimon wrote:What is the strength required of the magnets in order to prevent 3 to 5 MeV alphas from hitting the walls?
depends of specific energy (J/Kg) of the alphas:
(eV/Kg) × 1.60218E-19 → (J/Kg)
Using the specific energy to find velocity of products from nuclear reaction:
E=½mv² → v= ((E/m) × 2)0.5 → v= ((66.03921E12) ×2) 0.5 → v=11.49254E6 m/s
obs above: <sup>0.5</sup>
also, depends of specific ionization and magnet bore that you choose:
Defining the magnet bore about 1 meter (0.5 meter of internal radius) and using the specific ionization to find magnetic flux:
r=mv/qB → r= (v/B) × (m/q) → r= (v/B) / (q/m) → B=v/(r (q/m)) →
B=11.49254E6 / (0.5×10.80525E6) = 2.12721 Tesla
Specific energy and specific ionization are input parameters for calculations of magnetic flux and electric voltages.