Tom,Tom Ligon wrote:Chris,
You presume the reactions in question produce neutrons.
What is preposterous is believing these reactions are anything like what we normally consider to be fusion. Whatever is happening is not at all like happens between deuterium nuclei colliding in a hot plasma.
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What I rather strongly suspect is that you have not done these experiments yourself. First, you don't believe they are possible, and second, you think they are something other than what they are.
I have a very high regard for all of your contributions, which is why I am pained by what you are implying.
You seem, to me, to be suggesting that I am just firing off a critique without a proper analysis, faith-based, so to speak.
I'm actually quite offended by that (in a way that would otherwise be water off a duck's back, were it not someone like you making such a commentary).
My analysis has nothing whatsoever to do with the process involved, but it has everything to do with E=mc^2 and you need to come to understand that this is the basis of my critique.
If two deuterium nucleii can be coaxed together into a helium-4 by whatever method then you will get a ~23MeV excess of energy. It matters not at all whether this is in a hot plasma, or whether this can be done by incantations at midnight with bat's ears between your toes. The process just doesn't matter. Not at all. Not in the slightest.
So what you will end up with is 23MeV to turn into heat, one way or the other. Again, it just doesn't matter what particle mediates that, it will be 'radiation' whatever it is. The only conceivable way that this isn't going to radiate [dangerously, at measurable heat levels] is if that 23MeV is somehow magically carried away by many thousands of lower energy particles. If you are suggesting a 4He fires off with 23MeV, then that *is* radiation and it will induce many follow-on nuclear reactions. I mean, Rutherford was transforming N to O with just pissy little alphas from another decay. Try hammering a 23MeV alpha into something! It has a small range because it gives up its energy so effectively to what it's hitting - not because it is a lesser radioactive hazard but because it is a greater one.
But this is STILL fairy stories - if you observe two deuterium nucleii in "their" inertial frame (viz, the one in which they have the least KE sum) then they will come together and just sit there, stationary, in that inertial frame. They CAN'T shoot off at 23MeV worth of KE, it defeats the laws of momentum conservation. In the real world, that means they have to give up the energy as hv.
So I repeat again, for very specific and damned good objective reasons, that there is no possible way that a claim for measurable heat *from an unguarded nuclear process*, from someone who is still alive, is not bogus.
But I repeat and call your attention to what I wrote - I have no complaint with the experiments and look upon them with interest. It is the claims that are utter rubbish.
Though I will also add this; let us say that there *is* excess heat and that there *is* evidence of some nuclear process at play. What is the presumption then that both are from the same cause? If someone were to come to me and say "hey, most of this heat is some complex chemistry we don't quite understand and, by the way, there are a very small number of nuclear reactions as well", well, maybe I could listen to that. But I absolutely stand by what I say, and I say it for objective reasons, there is no way an unguarded nuclear process of D+D->4He can be observed to generate heat by anyone alive. To say otherwise is as daft as saying the Sun burns coal. It is not at all a "faith based" observation, and I am very riled that you'd suggest it may be so. If you think I am wrong then just say "I think your objective analysis is wrong": THAT I can handle!
But to say my analysis is driven by some in-built anti-quack faith-based belief thing??... Of all people to say that to! You're throwing eggs at the wrong guy there.