Of course not. You could linearly accelerate M-E thrusters up to high speed, crash them into a barrier, and run a steam turbine off the resulting heat. There are tons of ways. I chose the flywheel as a convenient, easy-to-work example. It does have the disadvantage that the rotational motion muddies the water a bit with the non-inertial nature of the thruster's reference frame (not the analysis reference frame) - perhaps I should have used a flat drive belt... the answer would be the same... in fact the math is the same...ladajo wrote:You do not need a flywheel to convert thrust to power.
Quit trying to use conservation of energy as if it were a separate physical law. It's inherent in Newtonian mechanics. And I just used Newtonian mechanics to CONCLUSIVELY PROVE that a locally over-unity device is possible using Mach-effect thrusters as a black box. Read it again.Skipjack wrote:I still dont get it. If you apply a counter- force to your ME- thruster without putting the same amount of energy into it, it will just slow down and ultimately stop.
A car interacts with a surface at a certain relative velocity. The power required to develop a certain accelerative force, neglecting losses, is simply the dot product of the desired force with the relative velocity.It uses the reast of the universe of a reaction mass, yes, but so does a wheel of a car with earth (if you want it that way).
If you put a horizontal wheel here on earth and then used a car to rotate the wheel and produce energy, you too have to keep pushing the gas pedal on the car, or the car will stop. I would assume that that same would be true for the ME- thruster and a flywheel in space.
Here's the money question: How fast is the "rest of the universe" moving relative to a Mach-effect thruster? Assuming your thruster generates a reliable force F when fed a certain quantity of power, what's the upper limit on v in F·v? (As it turns out, the answer is 1/E, where E is the thrust efficiency in N/W - which is a characteristic of the thruster, independent of what the thruster is doing or how fast it's moving in what direction. This may not be the actual average interaction-weighted relative velocity if something funky and relativistic and mind-bending happens to balance out the energy, but it is the effective average interaction-weighted relative velocity.)
If you understand mechanical work, you will now see that trying to discuss the M-E thruster as a "power amplifier" without specifying its mode of use is nonsense.
For example, if you use an M-E thruster to push against a reinforced concrete wall, you will not get any energy out, because it is doing no local work. Distant matter is being shoved in the other direction, but that does us no good. (Well, technically it's probably doing more work on the Earth than on the distant mass, but it still does us no good.)
On the other hand, if you have the M-E thruster push on something that's moving faster than 1/E, you will get more energy out than you put in. This comes from the distant mass that is moving in the same direction as the thruster at about the same speed, and thus already has kinetic energy in the local reference frame. Some of that energy is being transferred to the object being pushed on, with the energy input to the thruster as a mere enabler.
Now do you understand why I posited that the mechanism of operation of the thruster would act preferentially on matter near the thruster's velocity? If something like that is not true, something really funky is going on (you know, assuming it works at all, and Woodward isn't simply barking up the wrong tree...)